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O(max_level) where max_level refers to the maximum number of elements in any level of a binary tree. O(N) where N is the number of nodes in the given binary tree. } Level order traversal of BT: 0 1 2 3 4 5 6 Time Complexity *Function which print level order of the given tree*/

Node(int value)// create a node using new Node *Structure of Node of BT which contain pointer to left child and right child and a data for node.*/ Implementation For Level Order Traversal of Binary Tree /*C++ Implementation to prin the BFS of given binary tree*/ Repeat it till the size of the queue is not equal to null. After that pop the node from the queue and add it to BFS if it is not visited and add it’s all neighbor (unvisited) to queue. We start from root then we insert root into BFS and insert all neighbors of that node to queue. We are moving from left to right from every level and print the values:īy the use of the Queue data structure, we find the level order traversal. BFS is a level order traversal in which we visit the nodes of a binary tree from left to right at every level. This is a C Program to solve fractional knapsack problem. Do we already know about what actually BFS is? if not then don’t need to feel bad just read the whole article and visit our previous articles for better understanding. Level Order Traversal of a given binary tree is the same as the BFS of the binary tree.